Respuesta :

[tex]\begin{gathered} \text{ We have to reexpress the equation as an exponential equation; } \\ \log _9(2x-7)=2x-3 \\ 9^{\log _9(2x-7)}=9^{2x-3} \\ 2x-7=9^{2x-3} \end{gathered}[/tex][tex]\begin{gathered} \text{remember that } \\ a^{\log _a(b)}=b \\ \text{ "Exponential is the inverse operation of logarithm"} \end{gathered}[/tex]