The momentum of first player can be given as,
[tex]p_1=m_1v[/tex]The momentum of second player can be given as,
[tex]p_2=m_2v[/tex]The total momentum of both the players can be given as,
[tex]p=p_1+p_2[/tex]Plug in the known expressions,
[tex]\begin{gathered} p=m_1v+m_2v \\ =(m_1+m_2)v \end{gathered}[/tex]Substitute the known values,
[tex]\begin{gathered} p=(89.3\text{ kg+94.8 kg)(8.32 m/s)} \\ =(184.1\text{ kg)(8.32 m/s)}(\frac{1\text{ N}}{1kgm/s^2}) \\ =1531.7\text{ Ns} \end{gathered}[/tex]Thus, the total momentum of both the players is 1531.7 Ns.
