Respuesta :

semsee45

Answer:

A.  56

Step-by-step explanation:

Let the three consecutive integers be:

  • x
  • x + 1
  • x + 2

Given:

  • The sum of three consecutive integers is 30 more than twice the smallest integer.

Create an equation with the given information and solve for x:

[tex]\implies x+(x+1)+(x+2)=2x+30[/tex]

[tex]\implies 3x+3=2x+30[/tex]

[tex]\implies 3x+3-2x=2x+30-2x[/tex]

[tex]\implies x+3=30[/tex]

[tex]\implies x+3-3=30-3[/tex]

[tex]\implies x=27[/tex]

Therefore, the three consecutive integers are:

  • 27, 28 and 29.

So the sum of the first and last integer is:

[tex]\implies 27+29=56[/tex]

ItzTds

Answer:

a) 56 --- (27, 28, 29)

Step-by-step explanation:

Forming the equation,

→ x + (x + 1) + (x + 2) = 2x + 30

Now the value of x will be,

→ x + (x + 1) + (x + 2) = 2x + 30

→ x + x + 1 + x + 2 = 2x + 30

→ 3x - 2x = 30 - 3

→ [ x = 27 ]

The last integer will be,

→ x + 2

→ 27 + 2 = 29

Sum of first and last integer is,

→ x + (x + 2)

→ 27 + (27 + 2)

→ 27 + 29 = 56

Hence, required answer is 56.

Otras preguntas