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if a normal distribution has a mean of 62 and a standard deviation of 12 what is the z-score for a value of 80
a:1
b:1.5
c:2
d:0.5

Respuesta :

Answer with explanation:

[tex]\text{Mean}=\mu = 62\\\\ \text{standard deviation}=\sigma=12\\\\ \bar X=80\\\\Z_{score}=\frac{\bar X -\mu}{\sigma}\\\\Z_{score}=\frac{80-62}{12}\\\\Z_{score}=\frac{18}{12}\\\\Z_{score}=1.5[/tex]

Option B:→ 1.5

Answer:

Option B:→ 1.5

Step-by-step explanation:

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