Answer:
The linear equations are 2s + 5b = 13 , 4s + 3b = 12 and the weight of a steel ball is 1.5 pound , the weight of the brass ball is 2 pound .
Step-by-step explanation:
As
s is the weight of a steel ball and b is the weight of a brass ball.
As given
A bag contains two steel balls and five brass balls.
The total weight of the bag is 13 pounds.
Equation becomes
2s + 5b = 13
As given
If two steel balls are added and two brass balls are removed, the bag’s weight decreases to 12 pounds.
4s + 3b = 12
Thus linear equation becomes
2s + 5b = 13
4s + 3b = 12
Thus multiply 2s + 5b = 13 by 2 and subtracted from 4s + 3b = 12 .
4s - 4s + 3b - 10b = 12 - 26
-7b = -14
[tex]b = \frac{14}{7}[/tex]
b = 2 pound
Put the value of b in the equation 2s + 5b = 13 .
2s + 5 × 2 = 13
2s + 10 = 13
2s = 13 - 10
2s = 3
[tex]s = \frac{3}{2}[/tex]
s = 1.5 pound
Therefore the linear equations are 2s + 5b = 13 , 4s + 3b = 12 and the weight of a steel ball is 1.5 pound , the weight of the brass ball is 2 pound .
