Respuesta :
The mean of the sample is 15.4 and the standard deviation of the sample is 2.87. This shows that the population parameters of the sample is lower and is less dispersed.
Answer:
Mean is [tex]\overline{x} =15.4[/tex] and standard deviation is 3.02581485
Step-by-step explanation:
Given mean is 19.4 and standard deviation is 5.8
the given data are: - 12, 15, 17, 20, 13, 11, 18, 19, 15, 14
Mean of given data is calculated as :-
[tex]\overline{x} =\frac{1}{n}\sum_{i=1}^{n}x[/tex]
[tex]\overline{x} =\frac{12+15+17+20+13+11+18+19+15+14}{10}[/tex]
[tex]\overline{x} =\frac{12+15+17+20+13+11+18+19+15+14}{10}[/tex]
[tex]\overline{x} =\frac{154}{10}[/tex]
[tex]\overline{x} =15.4[/tex]
Mean is [tex]\overline{x} =15.4[/tex]
standard deviation is calculated as :-
[tex]s=\sqrt{\frac{1}{n-1}\sum_{i=1}^{n}(x-\overline{x})^{2}[/tex]
the sum of [tex](x-\overline{x})^{2}[/tex] is performed in figure-1
[tex]s=\sqrt{\frac{1}{10-1}\sum_{i=1}^{n}(\frac{412}{5})[/tex]
[tex]s=\sqrt{\frac{1}{9}\times\frac{412}{5}[/tex]
[tex]s=\sqrt{(\frac{412}{45})[/tex]
[tex]s=\sqrt{(\frac{412}{45})[/tex]
[tex]s=3.02581485[/tex]
standard deviation is 3.02581485
