Answer:
Explanation:
Given:
velocity (v) = 60 km/h
= (60 × 1000 ÷ 3600) m/s
= [tex]\frac{50}{3} \ m/s[/tex]
efficiency (η) = 25%
mass (m) = 1000 kg
Power in physics means the amount of Energy/Work done per unit Time. In another words, the SI unit is Joule/second which can also be written as Watt.
The Power done by the engine in this question can be defined as: moving the 1000 kg car by [tex]\frac{50}{3}[/tex] km in 1 second.
[tex]\boxed{Power\ (P)=\frac{Energy}{time\ (t)} }[/tex]
[tex]\displaystyle P=\frac{Force\ (F)\times distance\ (s)}{t}[/tex]
[tex]\displaystyle P=\frac{mass\ (m)\times gravitation\ (g)\times distance\ (s)}{t}[/tex]
[tex]\displaystyle P=\frac{1000\times9.8\times\frac{50}{3} }{1}[/tex]
[tex]P=163,333\frac{1}{3} \ W[/tex]
[tex]\boxed{P=\eta\cdot P_{out}}[/tex]
[tex]163333\frac{1}{3} =25\%P_{out}[/tex]
[tex]P_{out}=653,333\frac{1}{3} \ W[/tex]
