The electron microscope has been widely used to obtain highly magnified images of biological and other types of materials. when an electron is accelerated through a particular potential field, it attains a speed of 4.15 106 m/s. what is the characteristic wavelength of this electron?
Answer: For this problem, we use the equation λ = h/mv.
where λ is wavelength, h is Planck's constant, v is the velocity and m is the mass.
just plug the numbers in: λ = (6.63x10^-34)/((9.11x10^-31)*(4.15x10^6)
