You only have to sum the expressions of the two functions:
[tex] (f+g)(x) = f(x)+g(x) = \dfrac{x}{2}-3 + 3x^2 + x - 6 = 3x^2+\dfrac{3x}{2}-9 [/tex]
The sum of the function (f + g)(x) is; 3x² + ³/₂x - 9
We are given the functions;
f(x) = ¹/₂x - 3
g(x) = 3x² + x - 6
Thus the sum of the functions is;
(f + g)(x) = f(x) + g(x)
⇒ ¹/₂x - 3 + 3x² + x - 6
⇒ 3x² + ³/₂x - 9
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