The graph of the function f(x) = ax2 + bx +c (where a, b, and c are real and nonzero) has two x-intercepts. Explain how to find the other x-intercept if one x-intercept is at (-b/a2 +3,0)

-b/2a is the formula to find the vertex of a parabola. If one of the intercepts is at (-b/2a + 3, 0), the other one must be at (-b/2a - 3, 0), since the two x-intercepts have to be the same distance from the vertex.

Answer Link

AFOKE88 AFOKE88 · Answer 2 · 2021-10-21T19:40:04+02:00

The method to find the other x-intercept for the function f(x) = ax² + bx + c is given in the explanation below the answer.

The other x-intercept is; ((-b/2a - 3), 0)

We are given the equation of the function;

f(x) = ax² + bx + c

where a, b and c are real numbers and non - zero

Now, this is a quadratic equation that has 2 roots and it means there will be two x-intercepts.

Also, in quadratic equations, the formula to find the x-coordinate of the line of symmetry of the graph is;

x = -b/2a

The line of symmetry divides the graph curve into 2 equal parts at the vertex. This means the two x - intercepts will be the same distance from the x-coordinate of the vertex or line of symmetry but on opposite sides.

Thus, if one x-intercept is at ((-b/2a + 3), 0), then the other coordinate using the line of symmetry reason above is; ((-b/2a - 3), 0)

Read more at; https://brainly.com/question/23976116