While parachuting, a 66.0-kg person experiences a downward acceleration of 2.60 m/s2. 1) what is the downward force on the parachute from the person? (express your answer to three significant figures?
For Newton's second law, the force experienced by the person is equal to the product between his mass and his acceleration: [tex]F=ma[/tex] Using [tex]m=66 kg[/tex] and [tex]a=2.60 m/s^2[/tex], the downward force is [tex]F=(66 kg)(2.60 m/s^2)=172 N[/tex]
