[tex]a = d {(1 + \frac{interest \: rate}{months} ) }^{months \times years}[/tex]
[tex]a = 1000{(1 + 0.048 \div 12)}^{12 \times 1} [/tex]
[tex]a = 1000(1 + 0.004)^{12}[/tex]
[tex]a = 1000 \times 1.049[/tex]
[tex]1 \: year = 1049.07[/tex]
[tex]2 \: years = 1,100.55[/tex]
the answer is B