The solution to the problem is as follows:
5log2(k) = log2(k^5)
8log2(m)= log2(m^8)
10log2(n)= log2(n^10)
now to subtract logs, you divide the arguments, keeping the same vase.
To add logs, multiply the arguments.
So log2(k^5)- log2(m^8)+ log2(n^10)= log2[k^5* n^10)/m^8]
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