Respuesta :
The volume will decrease by a factor of 4
What is the effect of the following on the volume of 1 mol of an ideal gas?
Given:
P₁ = 760 KPa
P₂ =202KPa
The temperature changes from 37°C to 155 K
P₁ = 760 torr.
Ideal gas equation:
PV = nRT
where;
nR is constant
P= pressure
V= volume
T= temperature
n = number of moles
On adding values:
(P₁V₁/T₁)=(P₂V₂/T₂)
V₁/V₂ = P₂/P₁ * T₁/T₂
V₁/V₂ = (202/101)*(310/155)
V₁/V₂ = 4
Therefore, the volume has decreased by a factor of 4
What volume, at STP, does one mole of any ideal gas occupy?
The most typical illustration is the molar volume of a gas at STP, which is equal to 22.4 L for 1 mole of any ideal gas at a temperature of 273.15 K and a pressure of 1.00 atm.
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